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NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions RR ACADEMY MEERUT FOR JOIN CLASSES CALL@8393068250

NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.1

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.3

Question 1

Solution 1
(i)     2, 7, 12 ,…, to 10 terms
For this AP,
a = 2
d = a2 – a1 = 7 – 2 = 5 
n = 10
We know that,
(ii)     –37, –33, –29 ,…, to 12 terms
For this AP,
a = –37
d = a2 – a1 = (–33) – (–37)
 = – 33 + 37 = 4 
n = 12
We know that,

(iii)   0.6, 1.7, 2.8 ,…, to 100 terms
For this AP,
a = 0.6
d = a2 – a1 = 1.7 – 0.6 = 1.1  
n = 100
We know that,



Question 2

Solution 2

Question 3

Solution 3



Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10
(i)
(ii)

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.4

Question 1

Solution 1

Question 2
The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. 

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5


Solution 5

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