NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.1
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.2
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9
Solution 9
Question 10
Solution 10
Question 11
Solution 11
Question 12
Solution 12
Question 13
Solution 13
Question 14
Solution 14
Question 15
Solution 15
Question 16
Solution 16
Question 17
Solution 17
Question 18
Solution 18
Question 19
Solution 19
Question 20
Solution 20
NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.3
Question 1
Solution 1
(i) 2, 7, 12 ,…, to 10 terms
For this AP,
a = 2
d = a2 – a1 = 7 – 2 = 5
n = 10
We know that,
(ii) –37, –33, –29 ,…, to 12 terms
For this AP,
a = –37
d = a2 – a1 = (–33) – (–37)
= – 33 + 37 = 4
n = 12
We know that,
(iii) 0.6, 1.7, 2.8 ,…, to 100 terms
For this AP,
a = 0.6
d = a2 – a1 = 1.7 – 0.6 = 1.1
n = 100
We know that,
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9
Solution 9
Question 10
Solution 10
(i)
(ii)
Question 11
Solution 11
Question 12
Solution 12
Question 13
Solution 13
Question 14
Solution 14
Question 15
Solution 15
Question 16
Solution 16
Question 17
Solution 17
Question 18
Solution 18
Question 19
Solution 19
Question 20
Solution 20
NCERT Solution for Class 10 Mathematics Chapter 5 - Arithmetic Progressions Page/Excercise 5.4
Question 1
Solution 1
Question 2
The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP.
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
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