Directions (1-5): The following bar graph shows the percentage of boys and girls appeared for Class X exam for the period of five years 2005-2009. The line shows the total number of students appeared and the table shows the total students passed and percentage of boys and girls passed in the exam.
Q1. What is the number of girls who failed in the year 2007?
(a) 75
(b) 80
(c) 85
(d) 90
(e) None of these
Q2. What is the sum of girls passed and boys failed in the year 2009?
(a) 546
(b) 556
(c) 566
(d) 576
(e) None of these
Q3. What is the difference between the total boys appeared and the total boys passed in the period of five years?
(a) 1146
(b) 1156
(c) 1166
(d) 1176
(e) None of these
Q4. What is the ratio of the total boys appeared in the year 2009 to the total girls passed in the year 2006?
(a) 7 : 5
(b) 7 : 4
(c) 7 : 3
(d) 7 : 2
(e) None of these
Q5. The number of boys passed in the year 2005 is what per cent more than the number of girls appeared in the year 2006?
(a) 10%
(b) 20%
(c) 25%
(d) 40%
(e) None of these
Directions (6-15): What should come in place of question mark (?) in the following questions:
Q6. 4 + 4.44 + 0.4 + 44.04 + 444 = ?
(a) 486.48
(b) 496.88
(c) 486.88
(d) 496.84
(e) None of these
Q7. (?)^2 + (65)^2 = (160)^2 – (90)^2 – 7191
(a) 72
(b) 68
(c) 6084
(d) 78
(e) 82
Q8. 0.07 % of 1250 – 0.02 % of 650 = ?
(a) 0.745
(b) 0.875
(c) 0.545
(d) 0.695
(e) None of these
Q9. sqroot(6.25) / 0.5 = ?/10
(a) 5
(b) 500
(c) 50
(d) 2.5
(e) None of these
Q10. 1/8 * (223 + ?) = 73
(a) 361
(b) 371
(c) 341
(d) 391
(e) None of these
Q11. cuberoot(12167) * sqroot(16384) = ? * 11.5
(a) 204
(b) 234
(c) 286
(d) 256
(e) None of these
Q12. [18 * 14 - 6 * 8] / [488 / 4 - 20] = ?
(a) 3
(b) 2.5
(c) 4
(d) 8
(e) None of these
Q13. sqroot(7225) * 1/5 + (45)^2 = ?
(a) 2058
(b) 2042
(c) 2040
(d) 2038
(e) None of these
Q14. 25.6 % of 250 + sqroot(?) =119
(a) 3125
(b) 3025
(c) 55
(d) 65
(e) 4225
Q15. 7428 * 3/4 * 2/9 * ? = 619
(a) 0.2
(b) 0.8
(c) 0.5
(d) 2.4
(e) 1.5
S1. Ans.(c)
Sol. Total number of Girls who appeared in 2007 = 1000/100 * 36 = 360
Total number of Girls who passed in 2007 = 500/100 * 55 = 275
Total number of Girls who failed = 360 – 275 = 85
S2. Ans.(a)
Total number of girls passed in 2009 = 288
Total number of boys failed in 2009 = 770 – 512 = 258
Total sum = 288 + 258 = 546
S3. Ans.(e)
Sol. Total number of boys who appeared in all 5 years = 2925
Total number of boys who passed in all 5 years = 1739
Total difference = 2925 – 1739 = 1186
S4. Ans.(c)
Sol. Required Ratio = 770 : 330 = 7:3
S5. Ans.(b)
Sol. Number of boys passed in 2005 = 480
Number of girls appeared in 2006 = 400
Req % = (480 - 400)/400 * 100 = 20%
S6. Ans.(b)
Sol. 4 + 4.44 + 0.4 + 44.04 + 444 = 496.88
S7. Ans.(d)
Sol. (?)^2 = 25600 – 8100 – 7191 – 4225 = 6084
? = 78
S8. Ans.(a)
Sol. ? = 0.875 – 0.13 = 0.745
S9. Ans.(c)
Sol. 2.5/0.5 * 10 = ?
? = 50
S10. Ans.(a)
Sol. (223 + ?) = 73 * 8 = 584
? = 584 – 223 = 361
S11. Ans.(d)
Sol. 23 * 128 = ? * 11.5
? = 256
S12. Ans.(e)
Sol. (252 – 48)/(122 – 20) = 204/102 = 2
S13. Ans.(b)
Sol. 85/5 + 2025 = 2042
S14. Ans.(b)
Sol. 64 + sqroot(?) =119
sqroot(?) = 55
? = 3025
S15. Ans.(c)
Sol. 7428 * 3/4 * 2/9 * 1/619 = 1/?
? = 0.5
Q1. What is the number of girls who failed in the year 2007?
(a) 75
(b) 80
(c) 85
(d) 90
(e) None of these
Q2. What is the sum of girls passed and boys failed in the year 2009?
(a) 546
(b) 556
(c) 566
(d) 576
(e) None of these
Q3. What is the difference between the total boys appeared and the total boys passed in the period of five years?
(a) 1146
(b) 1156
(c) 1166
(d) 1176
(e) None of these
Q4. What is the ratio of the total boys appeared in the year 2009 to the total girls passed in the year 2006?
(a) 7 : 5
(b) 7 : 4
(c) 7 : 3
(d) 7 : 2
(e) None of these
Q5. The number of boys passed in the year 2005 is what per cent more than the number of girls appeared in the year 2006?
(a) 10%
(b) 20%
(c) 25%
(d) 40%
(e) None of these
Directions (6-15): What should come in place of question mark (?) in the following questions:
Q6. 4 + 4.44 + 0.4 + 44.04 + 444 = ?
(a) 486.48
(b) 496.88
(c) 486.88
(d) 496.84
(e) None of these
Q7. (?)^2 + (65)^2 = (160)^2 – (90)^2 – 7191
(a) 72
(b) 68
(c) 6084
(d) 78
(e) 82
Q8. 0.07 % of 1250 – 0.02 % of 650 = ?
(a) 0.745
(b) 0.875
(c) 0.545
(d) 0.695
(e) None of these
Q9. sqroot(6.25) / 0.5 = ?/10
(a) 5
(b) 500
(c) 50
(d) 2.5
(e) None of these
Q10. 1/8 * (223 + ?) = 73
(a) 361
(b) 371
(c) 341
(d) 391
(e) None of these
Q11. cuberoot(12167) * sqroot(16384) = ? * 11.5
(a) 204
(b) 234
(c) 286
(d) 256
(e) None of these
Q12. [18 * 14 - 6 * 8] / [488 / 4 - 20] = ?
(a) 3
(b) 2.5
(c) 4
(d) 8
(e) None of these
Q13. sqroot(7225) * 1/5 + (45)^2 = ?
(a) 2058
(b) 2042
(c) 2040
(d) 2038
(e) None of these
Q14. 25.6 % of 250 + sqroot(?) =119
(a) 3125
(b) 3025
(c) 55
(d) 65
(e) 4225
Q15. 7428 * 3/4 * 2/9 * ? = 619
(a) 0.2
(b) 0.8
(c) 0.5
(d) 2.4
(e) 1.5
Solutions
S1. Ans.(c)
Sol. Total number of Girls who appeared in 2007 = 1000/100 * 36 = 360
Total number of Girls who passed in 2007 = 500/100 * 55 = 275
Total number of Girls who failed = 360 – 275 = 85
S2. Ans.(a)
Total number of girls passed in 2009 = 288
Total number of boys failed in 2009 = 770 – 512 = 258
Total sum = 288 + 258 = 546
S3. Ans.(e)
Sol. Total number of boys who appeared in all 5 years = 2925
Total number of boys who passed in all 5 years = 1739
Total difference = 2925 – 1739 = 1186
S4. Ans.(c)
Sol. Required Ratio = 770 : 330 = 7:3
S5. Ans.(b)
Sol. Number of boys passed in 2005 = 480
Number of girls appeared in 2006 = 400
Req % = (480 - 400)/400 * 100 = 20%
S6. Ans.(b)
Sol. 4 + 4.44 + 0.4 + 44.04 + 444 = 496.88
S7. Ans.(d)
Sol. (?)^2 = 25600 – 8100 – 7191 – 4225 = 6084
? = 78
S8. Ans.(a)
Sol. ? = 0.875 – 0.13 = 0.745
S9. Ans.(c)
Sol. 2.5/0.5 * 10 = ?
? = 50
S10. Ans.(a)
Sol. (223 + ?) = 73 * 8 = 584
? = 584 – 223 = 361
S11. Ans.(d)
Sol. 23 * 128 = ? * 11.5
? = 256
S12. Ans.(e)
Sol. (252 – 48)/(122 – 20) = 204/102 = 2
S13. Ans.(b)
Sol. 85/5 + 2025 = 2042
S14. Ans.(b)
Sol. 64 + sqroot(?) =119
sqroot(?) = 55
? = 3025
S15. Ans.(c)
Sol. 7428 * 3/4 * 2/9 * 1/619 = 1/?
? = 0.5
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